If you are not deep in #lambdaMOO #mud I can imagine this being confusing:
>;me:tell("<lisp> \"AAmIFIHwnD8jU\" (moo::moo \":dances\")");
<lisp> "AAmIFIHwnD8jU" (moo::moo ":dances")
=> 0
Wizard dances
In MOO,
; 1 + 1;
will
=> 2
and have no output.
However in my case, I am using me:tell("string"); which calls tell on me obviously. Then what I am telling myself is:
<lisp> "AAmIFIHwnD8jU" (moo::moo ":dances")
I hooked to moo.el to eat
<lisp> "AAmIFIHwnD8jU"
and send
(moo::moo ":dances")
to lisp/