Refurio AnachroRefurioAnachro@mathstodon.xyz
Nov 15, 2026, 6:15 PMThanks! I have no intuition about the obstructions, does it get even easier for hyperbolic arrangements? I tend to guess it doesn't, but I can't tell why.
Thanks! I have no intuition about the obstructions, does it get even easier for hyperbolic arrangements? I tend to guess it doesn't, but I can't tell why.
@RefurioAnachro It does, actually. The reason is that there is an infinite zoo of reflection groups in hyperbolic space. Each gives a simplicial line arrangement, which in turn is dual to such a tiling with inscribed centrally-symmetric polygons. The sphere and plane are the hard case.